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% golfers.mzn
% vim: ft=zinc ts=4 sw=4 et tw=0
% Ralph Becket
% Mon Oct 29 13:56:25 EST 2007
%
% The social golfers problem, see
% http://www.dcs.st-and.ac.uk/~ianm/CSPLib/prob/prob001/data.txt
%
% A club has a number of golfers that play rounds in groups (the number of
% golfers is a multiple of the number of groups). Each round, a golfer
% plays with a group of different people, such that the same pair of golfers
% never play together twice.
include "globals.mzn";
int: n_groups; % The number of groups.
int: n_per_group; % The size of each group.
int: n_rounds; % The number of rounds.
int: n_golfers = n_groups * n_per_group;
set of int: rounds = 1..n_rounds;
set of int: golfers = 1..n_golfers;
set of int: places = 1..n_golfers;
array [rounds, places] of var golfers: round_place_golfer;
array [golfers, golfers] of var 0..n_rounds: golfer_golfer_round;
% Each member of each group must be distinct.
%
constraint
forall (r in rounds) (
alldifferent (p in places) (round_place_golfer[r, p])
);
% Break some symmetry by strictly ordering each group in each round.
%
constraint
forall (r in rounds, p in places) (
if p mod n_per_group != 0
then round_place_golfer[r, p] < round_place_golfer[r, p + 1]
else true
endif
);
% Each pair can play together at most once.
%
constraint
forall (r in rounds, g in 0..(n_groups - 1), i, j in 1..n_per_group
where i < j) (
golfer_golfer_round[
round_place_golfer[r, n_per_group * g + i],
round_place_golfer[r, n_per_group * g + j]
] = r
);
solve
:: int_search([round_place_golfer[r, p] | r in rounds, p in places],
first_fail, indomain_min, complete)
satisfy;
output [
"Social golfers:\n\n",
"Groups : ", show(n_groups), "\n",
"No. per group : ", show(n_per_group), "\n",
"No. of rounds : ", show(n_rounds), "\n"
] ++ [
( if p = 1 then "\nround " ++ show(r) ++ ":" else "" endif ) ++
( if p mod n_per_group = 1 then " " else " " endif ) ++
show_int(2, round_place_golfer[r, p]) | r in rounds, p in places
];
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